# CBSEtips.in

## Thursday, 25 February 2021

### CBSE Class 7 Maths - MCQ and Online Tests - Unit 4 - Simple Equations

#### CBSE Class 7 Maths – MCQ and Online Tests – Unit 4 – Simple Equations

Every year CBSE students attend Annual Assessment exams for 6,7,8,9,11th standards. These exams are very competitive to all the students. So our website provides online tests for all the 6,7,8,9,11th standards’ subjects. These tests are also very effective and useful for those who preparing for any competitive exams like Olympiad etc. It can boost their preparation level and confidence level by attempting these chapter wise online tests.

These online tests are based on latest CBSE syllabus. While attempting these, our students can identify their weak lessons and continuously practice those lessons for attaining high marks. It also helps to revise the NCERT textbooks thoroughly

#### CBSE Class 7 Maths – MCQ and Online Tests – Unit 4 – Simple Equations

Question 1.
The solution of the equation 5p + 2 = 7 is
(a) 0
(b) 1
(c) -1
(d) 2

Hint:
5p + 2 = 71 ? 5p = 7 – 2 = 5
? p = $$\frac{5}{5}$$ = 1.

Question 2.
The solution of the equation 3p – 2 = 4 is
(a) 0
(b) 1
(c) 2
(d) 3

Hint:
3p – 2 = 4 ? 3p = 4 + 2 = 6
? P = $$\frac{6}{3}$$ = 2

Question 3.
Write the following statement in the form of an equation:
One fourth of n is 3 more than 2
(a) $$\frac { n }{ 4 }$$ – 2 = 3
(b) $$\frac { n }{ 4 }$$ + 2 = 3
(c) $$\frac { n }{ 2 }$$ – 4 = 3
(d) $$\frac { n }{ 2 }$$ + 4 = 3

Answer: (a) $$\frac { n }{ 4 }$$ – 2 = 3

Question 4.
Write the following statement in the form of an equation:
One third of a number plus 2 is 3
(a) $$\frac { m }{ 3 }$$ – 2 = 3
(b) $$\frac { m }{ 3 }$$ + 2 = 3
(c) $$\frac { m }{ 2 }$$ – 3 = 3
(d) $$\frac { m }{ 2 }$$ + 3 = 3

Answer: (b) $$\frac { m }{ 3 }$$ + 2 = 3

Question 5.
Write the following statement in the form of an equation:
Taking away 5 from x gives 10
(a) x – 5 = 10
(b) x + 5 = 10
(c) x – 10 – 5
(d) none of these

Answer: (a) x – 5 = 10

Question 6.
Write the following statement in the form of an equation:
Four times a number p is 8.
(a) 4P = 8
(b) P + 4 = 8
(c) p – 4 = 8
(d) p ÷ 4 = 8

Answer: (a) 4P = 8

Question 7.
Write the following statement in the form of an equation:
Add 1 to three times n to get 7
(a) 3n + 1 = 7
(b) 3n – 1 = 7
(c) 3n + 7 = 1
(d) none of these

Answer: (a) 3n + 1 = 7

Question 8.
Write the following statement in the form of an equation:
The sum of three times x and 10 is 13.
(a) 3x + 10 = 13
(b) 3x – 10 = 13
(c) 3x + 13 = 10
(d) none of these

Answer: (a) 3x + 10 = 13

Question 9.
Write the following statement in the form of an equation:
If you subtract 3 from 6 times a number, you get 9
(a) 3x – 6 = 9
(b) 6x – 3 = 9
(c) 6x + 3 = 9
(d) 3x + 6 = 9

Answer: (b) 6x – 3 = 9

Question 10.
The solution of the equation x – 6 = 1 is
(a) 1
(b) 6
(c) -7
(b) 7

Hint:
x – 6 = 1 ? x = 1 + 6 = 7.

Question 11.
The solution of the equation 5x = 10 is
(a) 1
(b) 2
(c) 5
(d) 10

Hint:
5x = 10 ? x = $$\frac{10}{5}$$ = 2

Question 12.
The solution of the equation 4p – 3 = 9 is
(a) 1
(b) 2
(c) 3
(d) 4

Hint:
4p – 3 = 9 ? 4p = 9 + 3 = 12
? p = $$\frac{12}{4}$$ = 3.

Question 13.
Write the following statement in the form of an equation:
The number b divided by 6 gives 5.
(a) $$\frac { b }{ 6 }$$ = 5
(b) b – 5 = 6
(c) 5b = 6
(d) b + 5 = 6

Answer: (a) $$\frac { b }{ 6 }$$ = 5

Question 14.
The solution of the equation x + 3 = 0 is
(a) 3
(b) -3
(c) 0
(d) 1

Hint:
x + 3 = 0 ? x = -3.

Question 15.
The solution of the equation p + 4 = 4 is
(a) 0
(b) 4
(c) -4
(d) 8

Hint:
p + 4 = 4 ? P = 4 – 4 = 0.

Question 16.
The solution of the equation m – 1 = 2 is
(a) 1
(b) 2
(c) 3
(d) 6

Hint:
m – 1 = 2 ? m = 2 + 1 = 3.

Question 17.
The solution of the equation 2m = 4 is
(a) 1
(b) 2
(c) -1
(d) -2

Hint:
2m = 4 ? m = $$\frac{4}{2}$$ = 2

Question 18.
The solution of the equation $$\frac { m }{ 3 }$$ = 3 is
(a) 3
(b) 6
(c) 9
(d) 12

Hint:
$$\frac{m}{3}$$ = 3 ? m = 3 × 3 = 9.

Question 19.
The solution of the equation = 6 is
(a) 6
(b) 7
(c) 14
(d) 3

Hint:
$$\frac{3m}{7}$$ = 6 ? 3m = 7 × 6 = 42
? m = $$\frac{42}{3}$$ = 14

Question 20.
The solution of the equation 3p + 5 = 8 is
(a) -1
(b) 1
(c) 3
(d) 5

Hint:
3p + 5 = 8 ? 3p = 8 – 5 = 3
? P = $$\frac{3}{3}$$ = 1 4p – 2 = 10

Question 21.
The solution of the equation 4p – 2 = 10 is
(a) 1
(b) 2
(c) 3
(d) 4

Hint:
4p – 2 = 10 ? 4p = 10 + 2 = 12
? p = $$\frac{12}{4}$$ = 3.

Question 22.
The solution of the equation 2p – 1 = 3 is
(a) 1
(b) 2
(c) 3
(d) 4

Hint:
2p – 1 = 3 ? 2p = 3 + 1 = 4
? p = $$\frac{4}{2}$$ = 2.

Question 23.
The solution of the equation $$\frac { m }{ 2 }$$ = 3 is
(a) 2
(b) 3
(c) 12
(d) 6

Hint:
$$\frac{m}{2}$$ = 3 ? m = 3 × 2 = 6.

Question 24.
The solution of the equation 7n + 5 = 12 is
(a) 0
(b) – 1
(c) 1
(d) 5

Hint:
7n + 5 = 12 ? 7n = 12 – 5
? 7n = 1 ? n = $$\frac{7}{7}$$ = 1.

Question 25.
The solution of the equation y – 4 = – 1 is
(a) 1
(b) 2
(c) 3
(d) 4

Hint:
y – 4 = -1 ? y = 4 – 1 = 3.

Question 26.
The solution of the equation y + 2 = -2 is
(a) 2
(b) -2
(c) 4
(d) -4

Hint:
y + 2 = -2 ? y = -2 – 2 = -4.

Question 27.
The solution of the equation 10t = -20 is
(a) 1
(b) -1
(c) 2
(d) -2

Hint:
10t = -20 ? t = –$$\frac{20}{10}$$ = -2

Question 28.
The solution of the equation $$\frac { z }{ 2 }$$ = $$\frac { 3 }{ 4 }$$ is
(a) $$\frac { 1 }{ 2 }$$
(b) $$\frac { 3 }{ 2 }$$
(c) $$\frac { 1 }{ 4 }$$
(d) $$\frac { 3 }{ 4 }$$

Answer: (b) $$\frac { 3 }{ 2 }$$
Hint:
$$\frac{z}{2}$$ = $$\frac{3}{4}$$ ? z = $$\frac{3×2}{4}$$ = $$\frac{3}{2}$$

Question 29.
The solution of the equation 2s = 0 is
(a) 2
(b) -2
(c) 0
(d) $$\frac { 1 }{ 2 }$$

Hint:
2s = 0 ? s = $$\frac{0}{2}$$ = 0.

Question 30.
The solution of the equation – $$\frac { p }{ 7 }$$ = 3 is
(a) -3
(b) -7
(c) -21
(d) 21

Hint:
–$$\frac{p}{7}$$ = 3 ? -p = 3 × 7 = 21
? p = -21

Question 31.
The solution of the equation 4x + 5 = 9 is
(a) 1
(b) 2
(c) 3
(d) 4

Hint:
4x + 5 = 9 ? 4x = 9 – 6 = 4
? x = $$\frac{4}{4}$$ = 1.

Question 32.
The solution of the equation 10 y – 20 = 30 is
(a) 1
(b) 2
(c) 3
(d) 5

Hint:
10y – 20 = 30 ? 10y = 30 + 20 = 50
? y = $$\frac{50}{10}$$ = 5.

Question 33.
The solution of the equation 3s + 6 = 0 is
(a) 1
(b) -1
(c) 2
(d) -2

Hint:
3s + 6 = 0
? 3s = -6 ? s = –$$\frac{6}{3}$$ = -2.

Question 34.
The solution of the equation 10p = 10 is
(a) 1
(b) – 1
(c) 10
(d) – 10

Hint:
10p = 10 ? p = $$\frac{10}{10}$$ = 1.

Question 35.
The solution of the equation 10p + 10 = 110 is
(a) 10
(b) -10
(c) 100
(d) 110

Hint:
10p + 10 = 110
? 10p = 110 – 10 = 100
? p = $$\frac{100}{10}$$ = 10.

Question 36.
The solution of the equation – 4 = 2 (p – 2) is
(a) 0
(b) 1
(c) 2
(d) 4

Hint:
-4 = 2(p – 2) ? p – 2 = –$$\frac{4}{2}$$ = -2
? p = -2 + 2 = 0.

Question 37.
The solution of the equation 0 = 4 + 4(m + 1) is
(a) 1
(b) -1
(c) 2
(d) -2

Hint:
0 = 4 + 4 (m + 1)
? 4(m + 1) = -4 ? m + 1 = –$$\frac{4}{4}$$ = -1
m = -1 – 1 = -2.

Question 38.
The solution of the equation 12p – 11 = 13 is
(a) 1
(b) 2
(c) 3
(d) 4

Hint:
12p – 11 = 13 ? 12p = 13 + 11 = 24
? p = $$\frac{24}{12}$$ = 2.

Question 39.
The solution of the equation 2 (m + 3) = 8 is
(a) 1
(b) 2
(c) 3
(d) 4

Hint:
2(m + 3) = 8 ? m + 3 = $$\frac{8}{2}$$ = 4
? m = 4 – 3 = 1.

Question 40.
The solution of the equation – 2(x + 3) = 4 is
(a) -2
(b) -3
(c) -4
(d) -5

Hint:
-2 (x + 3) = 4 ? x + 3 = $$\frac{4}{-2}$$ = -2
? x = -2 – 3 = -5.

Question 41.
The solution of the equation $$\frac { 5 }{ 2 }$$ x = 15 is
(a) 2
(b) 4
(c) 6
(d) 10

Hint:
$$\frac{5}{2}$$ x = 15 ? x = $$\frac{15×2}{5}$$ = 6

Question 42.
The solution of the equation 4(2 – x) = 4 is
(a) 1
(b) 2
(c) 3
(d) 4

Hint:
4 (2 – x) = 4 ? 2 – x = $$\frac{4}{4}$$ = 1
? x = 2 – 1 = 1.

Question 43.
The solution of the equation -4(2 + x) = 4 is
(a) -1
(b) -2
(c) -3
(d) -4

Hint:
-4(2 + x) = 4 ? 2 + x = $$\frac{4}{-4}$$ = -1
? x = -1 – 2 = -3.

Question 44.
The solution of the equation $$\frac { p }{ 2 }$$ + 1 = 3 is
(a) 1
(b) 2
(c) 3
(d) 4

Hint:
$$\frac{p}{2}$$ + 1 = 3 ? $$\frac{p}{2}$$ = 3 – 1 = 2
p = 2 × 2 = 4

Question 45.
The solution of the equation 3 m + 7=16 is
(a) 1
(b) 2
(c) 3
(d) 4

Hint:
3m + 7 = 16 ? 3m = 16 – 7 = 9
? m = $$\frac{9}{3}$$ = 3

Share: